Ok here is the asy one which I am sure many know:
You have 9 stones, one is lighter then the others, how do you tell using a scale and by using it just twice, which stone is lighter?
The next one is more difficult:
12 stones this time, one is a different weight but you do not know whether it is lighter or heavier, so how do you tell using a scal and using it 3 times which is a different weight?
Global Forums > General > An easy one and a more difficult
Only members can see names and photos
An easy one and a more difficult
Jun 29, 2006 @ 14:44
The text you are quoting:
Ok here is the asy one which I am sure many know:
You have 9 stones, one is lighter then the others, how do you tell using a scale and by using it just twice, which stone is lighter?
The next one is more difficult:
12 stones this time, one is a different weight but you do not know whether it is lighter or heavier, so how do you tell using a scal and using it 3 times which is a different weight?
SE1972Jun 29, 2006 @ 14:44
You have 9 stones, one is lighter then the others, how do you tell using a scale and by using it just twice, which stone is lighter?
The next one is more difficult:
12 stones this time, one is a different weight but you do not know whether it is lighter or heavier, so how do you tell using a scal and using it 3 times which is a different weight?
SE1972Jun 29, 2006 @ 14:44
Your Reply:
Only members can see names and photos
Re: An easy one and a more difficult
Post 1
Jun 29, 2006 @ 15:07
place 3 stones on each side, if they balance then place one of 3 remaining stones on each side , if they balance then the 1 remaining stone is the light or if they don't balance the individual is indicated.
If the 3 stones each side didn't balance then take the stones from the lighter side place one on each side and use the same deduction as above.
Will think about the other one at lunch
If the 3 stones each side didn't balance then take the stones from the lighter side place one on each side and use the same deduction as above.
Will think about the other one at lunch
The text you are quoting:
place 3 stones on each side, if they balance then place one of 3 remaining stones on each side , if they balance then the 1 remaining stone is the light or if they don't balance the individual is indicated.
If the 3 stones each side didn't balance then take the stones from the lighter side place one on each side and use the same deduction as above.
Will think about the other one at lunch
britabroad, Jun 29, 2006 @ 15:07
If the 3 stones each side didn't balance then take the stones from the lighter side place one on each side and use the same deduction as above.
Will think about the other one at lunch
britabroad, Jun 29, 2006 @ 15:07
Your Reply:
Only members can see names and photos
Re: An easy one and a more difficult
Post 2
Jun 29, 2006 @ 15:44
Good answer - the other one is complicated
The text you are quoting:
Good answer - the other one is complicated
SE1972, Jun 29, 2006 @ 15:44
SE1972, Jun 29, 2006 @ 15:44
Your Reply:
Only members can see names and photos
Re: An easy one and a more difficult
Post 3
Jun 29, 2006 @ 17:20
That was a tough one but you got it - the trick was dividing into 4 and mixing the groups.
The text you are quoting:
That was a tough one but you got it - the trick was dividing into 4 and mixing the groups.
SE1972, Jun 29, 2006 @ 17:20
SE1972, Jun 29, 2006 @ 17:20
Your Reply:
